Mathematics Relations and Functions 1 Mark Appeared in: 2026 (3 sets) If $f(x) = \begin{cases} \frac{x^{2} - 4x - 5}{x + 1}, & x \neq -1 \\ k, & x = -1 \end{cases}$ is continuous at $x = -1$, then the value of $k$ is : (A) Any real value (B) $6$ (C) $-1$ (D) $-6$