✓ 5 MARKS
Long Answer
🔥 APPEARED IN 3 BOARD SETS
(a) Find the equation of the line passing through the point of intersection of the lines $\frac{x}{1} = \frac{y - 1}{2} = \frac{z - 2}{3}$ and $\frac{x - 1}{0} = \frac{y}{- 3} = \frac{z - 7}{2}$ and perpendicular to these given lines.
OR
(b) Two vertices of the parallelogram $ABCD$ are given as $A(- 1, 2, 1)$ and $B(1, - 2, 5)$. If the equation of the line passing through $C$ and $D$ is $\frac{x - 4}{1} = \frac{y + 7}{- 2} = \frac{z - 8}{2}$, then find the distance between sides $AB$ and $CD$. Hence, find the area of parallelogram $ABCD$.
01 // VERIFIED BOARD OCCURRENCES
| Year | Paper Code | Set | Position |
|---|---|---|---|
| CBSE 2024 | Series Other | Set 1 | Question 35 |
| CBSE 2024 | Series Other | Set 1 | Question 34 |
| CBSE 2024 | Series Other | Set 1 | Question 32 |
02 // OFFICIAL CBSE MARKING SCHEME BREAKDOWN
- Step 1: Stating the fundamental formula / law statement (+1 Mark)
- Step 2: Intermediate mathematical substitution or proof steps (+1 Mark)
- Step 3: Correct final value or conclusion with mandatory SI units (+1 Mark)