Appeared in: 2023 (3 sets)
It is given that $X \begin{bmatrix} 3 & 2 \\ 1 & -1 \end{bmatrix} = \begin{bmatrix} 4 & 1 \\ 2 & 3 \end{bmatrix}$. Then matrix $X$ is :
(a) $\begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix}$
(b) $\begin{bmatrix} 0 & -1 \\ 1 & 1 \end{bmatrix}$
(c) $\begin{bmatrix} 1 & 1 \\ 1 & -1 \end{bmatrix}$
(d) $\begin{bmatrix} 1 & -1 \\ 1 & -1 \end{bmatrix}$