An organic compound 'A', with molecular formula $\text{C}_2\text{H}_6\text{O}$ reacts with active metals such as sodium to give compound 'B' and hydrogen gas. 'A' on treatment with iodine and sodium hydroxide gives 'C' and in presence of $\text{H}_2\text{SO}_4$ at $413\text{ K}$ gives 'D' ($\text{C}_4\text{H}_{10}\text{O}$). 'D' on reaction with excess of HI gives 'E'. Identify 'A', 'B', 'C', 'D' and 'E' and write all the reactions involved. OR

(a) Write the reagents which are used in the given conversions : (i) Phenol to $2, 4, 6 - \text{tribromophenol}$ (ii) Propene to propan-$1-\text{ol}$ (iii) Butan-$2-\text{one}$ to butan-$2-\text{ol}$ (b) Explain the mechanism of acid catalyzed hydration of alkene to form corresponding alcohol.