The conductivity of $0\cdot2\text{ M}$ solution of $\text{KCl}$ is $2\cdot48 \times 10^{-2}\text{ S cm}^{-1}$. Calculate its molar conductivity and degree of dissociation $(\alpha)$. Given : $\lambda^0_{\text{K}^+} = 73\cdot5\text{ S cm}^2\text{ mol}^{-1}$ $\lambda^0_{\text{Cl}^-} = 76\cdot5\text{ S cm}^2\text{ mol}^{-1}$

Year	Paper Code	Set	Position
CBSE 2024	Series 56-3	Set 1	Question 23
CBSE 2024	Series 56-3	Set 2	Question 27
CBSE 2024	Series 56-3	Set 3	Question 28

• Step 1: Stating the fundamental formula / law statement (+1 Mark)
• Step 2: Intermediate mathematical substitution or proof steps (+1 Mark)
• Step 3: Correct final value or conclusion with mandatory SI units (+1 Mark)