✓ 1 MARKS
MCQ
🔥 APPEARED IN 3 BOARD SETS
The value of k for which the function $f(x) = \begin{cases} x^2 \sin \frac{1}{x}, & x \neq 0 \\ k(x + 1), & x = 0 \end{cases}$$ is a continuous function, is :
A
$\frac{1}{4}$
B
2
C
$\frac{1}{2}$
D
0
01 // VERIFIED BOARD OCCURRENCES
| Year | Paper Code | Set | Position |
|---|---|---|---|
| CBSE 2026 | Series 65-3 | Set 1 | Question 7 |
| CBSE 2026 | Series 65-3 | Set 2 | Question 18 |
| CBSE 2026 | Series 65-3 | Set 3 | Question 11 |
02 // OFFICIAL CBSE MARKING SCHEME BREAKDOWN
- Step 1: Stating the fundamental formula / law statement (+1 Mark)
- Step 2: Intermediate mathematical substitution or proof steps (+1 Mark)
- Step 3: Correct final value or conclusion with mandatory SI units (+1 Mark)