✓ 5 MARKS
Long Answer
🔥 APPEARED IN 3 BOARD SETS
(a) (i) Carry out the following conversions : (1) Ethanal to But-2-en-1-al (2) Propanoic acid to 2-chloropropanoic acid (ii) An alkene with molecular formula $\text{C}_5\text{H}_{10}$ on ozonolysis gives a mixture of two compounds 'B' and 'C'. Compound 'B' gives positive Fehling test and also reacts with iodine and $\text{NaOH}$ solution. Compound 'C' does not give Fehling solution test but forms iodoform. Identify the compounds 'A', 'B' and 'C'. OR (b) (i) Distinguish with a suitable chemical test : (1) $\text{CH}_3\text{COCH}_2\text{CH}_3$ and $\text{CH}_3\text{CH}_2\text{CH}_2\text{CHO}$ (2) Ethanal and Ethanoic acid (ii) Write the structure of oxime of acetone. (iii) Identify A to D. $\text{CH}_3\text{COOH} \xrightarrow{\text{PCl}_5} \text{A} \xrightarrow{\text{H}_2 / \text{Pd-BaSO}_4} \text{B} \xrightarrow{\text{(i) CH}_3\text{MgBr}} \text{(ii) H}_3\text{O}^+ \text{C}$ and $\text{B} \xrightarrow{\text{LiAlH}_4} \text{D}$
01 // VERIFIED BOARD OCCURRENCES
| Year | Paper Code | Set | Position |
|---|---|---|---|
| CBSE 2023 | Series Other | Set 1 | Question 35 |
| CBSE 2023 | Series Other | Set 1 | Question 34 |
| CBSE 2023 | Series Other | Set 1 | Question 33 |
02 // OFFICIAL CBSE MARKING SCHEME BREAKDOWN
- Step 1: Stating the fundamental formula / law statement (+1 Mark)
- Step 2: Intermediate mathematical substitution or proof steps (+1 Mark)
- Step 3: Correct final value or conclusion with mandatory SI units (+1 Mark)