✓ 5 MARKS
Reasoning / Why
🔥 APPEARED IN 3 BOARD SETS
(a) (i) How will you bring about the following conversions :
(I) Bromobenzene to 1-phenylethanol
(II) Benzene to m-nitroacetophenone
(ii) An organic compound with the molecular formula $\text{C}_8\text{H}_8\text{O}$ forms 2,4-DNP derivative, reduces Tollens' reagent and undergoes Cannizzaro reaction. On vigorous oxidation with acidic or alkaline $\text{KMnO}_4$ it gives Benzene-1,2-dicarboxylic acid. Identify the compound and write the products when it undergoes Cannizzaro reaction.
(iii) Arrange the following compounds in increasing order of their acid strength :
$\text{C}_6\text{H}_5\text{COOH}, \text{O}_2\text{N} - \text{CH}_2 - \text{COOH}, \text{CF}_3 - \text{COOH}, \text{HCOOH}
OR
(b) (i) Write the products formed when benzaldehyde reacts with the following reagents :
(I) 2,4-Dinitrophenylhydrazine
(II) Acetophenone in the presence of dilute $\text{NaOH}$ followed by heating
(ii) Give reasons for the following :
(I) Benzoic acid does not undergo Friedel-Crafts reaction.
(II) Carboxylic acids have higher boiling point than alcohols of comparable molecular mass.
(iii) Write simple chemical test to distinguish between propanal and propanone.
01 // VERIFIED BOARD OCCURRENCES
| Year | Paper Code | Set | Position |
|---|---|---|---|
| CBSE 2026 | Series 56-4 | Set 1 | Question 32 |
| CBSE 2026 | Series 56-4 | Set 2 | Question 33 |
| CBSE 2026 | Series 56-4 | Set 3 | Question 31 |
02 // OFFICIAL CBSE MARKING SCHEME BREAKDOWN
- Step 1: Stating the fundamental formula / law statement (+1 Mark)
- Step 2: Intermediate mathematical substitution or proof steps (+1 Mark)
- Step 3: Correct final value or conclusion with mandatory SI units (+1 Mark)